Shift NaNs to the end of their respective rows

Question

I have a DataFrame like :

     0    1    2
0  0.0  1.0  2.0
1  NaN  1.0  2.0
2  NaN  NaN  2.0

---

What I want to get is

Answer 1

Here's a NumPy solution using justify -

In [455]: df
Out[455]: 
     0    1    2
0  0.0  1.0  2.0
1  NaN  1.0  2.0
2  NaN  NaN  2.0

In [456]: pd.DataFrame(justify(df.values, invalid_val=np.nan, axis=1, side='left'))
Out[456]: 
     0    1    2
0  0.0  1.0  2.0
1  1.0  2.0  NaN
2  2.0  NaN  NaN

If you want to save memory, assign it back instead -

df[:] = justify(df.values, invalid_val=np.nan, axis=1, side='left')

Answer 2

Your best easiest option is to use sorted on df.apply/df.transform and sort by nullity.

df = df.apply(lambda x: sorted(x, key=pd.isnull), 1)
df
     0    1    2
0  0.0  1.0  2.0
1  1.0  2.0  NaN
2  2.0  NaN  NaN

You may also pass np.isnan to the key argument.