c# Array.FindAllIndexOf which FindAll IndexOf

Question

I know c# has Array.FindAll and Array.IndexOf.

Is there a Array.FindAllIndexOf which returns int[]?

Answer 1

I'm aware that the question is answered already, this is just another way of doing it. note that I used ArrayList instead of int[]

// required using directives
using System;
using System.Collections;

String      inputString = "The lazy fox couldn't jump, poor fox!";
ArrayList   locations   =  new ArrayList();      // array for found indexes
string[] lineArray = inputString.Split(' ');     // inputString to array of strings separated by spaces

int tempInt = 0;
foreach (string element in lineArray)
{
     if (element == "fox")
     {
         locations.Add(tempInt);   // tempInt will be the index of current found index and added to Arraylist for further processing 
     }
 tempInt++;
}

Answer 2

No, there is not. But you can write your own extension method.

public static int[] FindAllIndexOf<T>(this T[] a, Predicate<T> match)
{
   T[] subArray = Array.FindAll<T>(a, match);
   return (from T item in subArray select Array.IndexOf(a, item)).ToArray();
}

and then, for your array, call it.

Answer 3

You can write something like :

string[] someItems = { "cat", "dog", "purple elephant", "unicorn" }; 
var selectedItems = someItems.Select((item, index) => new{
    ItemName = item,
    Position = index});

or

var Items = someItems.Select((item, index) => new{
    ItemName = item,
    Position = index}).Where(i => i.ItemName == "purple elephant");

Read : Get the index of a given item using LINQ