Regex to find text between second and third slashes

Question

I would like to capture the text that occurs after the second slash and before the third slash in a string. Example:

/ipaddress/databasename/

I need to capt

Answer 1

You can even more shorten the pattern by going this way:

[^/]+/(\w+)

Here \w includes characters like A-Z, a-z, 0-9 and _

I would suggest you to give SPLIT function a priority, since i have experienced a good performance of them over RegEx functions wherever it is possible to use them.

Answer 2

I know you specifically asked for regex, but you don't really need regex for this. You simply need to split the string by delimiters (in this case a backslash), then choose the part you need (in this case, the 3rd field - the first field is empty).

• cut example:

  cut -d '/' -f 3 <<< "$string"
  

• awk example:

  awk -F '/' {print $3} <<< "$string"
  

• perl expression, using split function:

  (split '/', $string)[2]
  

etc.

Answer 3

How you access it depends on your language, but you'll basically just want a capture group for whatever falls between your second and third "/". Assuming your string is always in the same form as your example, this will be:

/.*/(.*)/

If multiple slashes can exist, but a slash can never exist in the database name, you'd want:

/.*/(.*?)/

Answer 4

/.*?/(.*?)/

In the event that your lines always have / at the end of the line:

([^/]*)/$

Alternate split method:

split("/")[2]

Answer 5

you can use explode function with PHP or split with other languages to so such operation.

anyways, here is regex pattern:

/[\/]*[^\/]+[\/]([^\/]+)/

Answer 6

The regex would be:

/[^/]*/([^/]*)/

so in Perl, the regex capture statement would be something like:

($database) = $text =~ m!/[^/]*/([^/]*)/!;

Normally the / character is used to delimit regexes but since they're used as part of the match, another character can be used. Alternatively, the / character can be escaped:

($database) = $text =~ /\/[^\/]*\/([^\/]*)\//;