Get the decimal part from a double

Question

I want to receive the number after the decimal dot in the form of an integer. For example, only 05 from 1.05 or from 2.50 only 50 not 0.50

Answer 1

The simplest variant is possibly with Math.truncate()

double value = 1.761
double decPart = value - Math.truncate(value)

Answer 2

 string input = "0.55";
    var regex1 = new System.Text.RegularExpressions.Regex("(?<=[\\.])[0-9]+");
    if (regex1.IsMatch(input))
    {
        string dp= regex1.Match(input ).Value;
    }

Answer 3

There is a cleaner and ways faster solution than the 'Math.Truncate' approach:

double frac = value % 1;

Answer 4

Better Way -

        double value = 10.567;
        int result = (int)((value - (int)value) * 100);
        Console.WriteLine(result);

Output -

56

Answer 5

Why not use int y = value.Split('.')[1];?

The Split() function splits the value into separate content and the 1 is outputting the 2nd value after the .

Answer 6

Use a regex: Regex.Match("\.(?\d+)") Someone correct me if I'm wrong here