How do I read an entire InputStream into a byte array?
Java 8 way (thanks to BufferedReader and Adam Bien)
private static byte[] readFully(InputStream input) throws IOException {
try (BufferedReader buffer = new BufferedReader(new InputStreamReader(input))) {
return buffer.lines().collect(Collectors.joining("\n")).getBytes(<charset_can_be_specified>);
}
}
Note that this solution wipes carriage return ('\r') and can be inappropriate.
Java 9 will give you finally a nice method:
InputStream in = ...;
ByteArrayOutputStream bos = new ByteArrayOutputStream();
in.transferTo( bos );
byte[] bytes = bos.toByteArray();
You can use Apache Commons IO to handle this and similar tasks.
The IOUtils type has a static method to read an InputStream and return a byte[].
InputStream is;
byte[] bytes = IOUtils.toByteArray(is);
Internally this creates a ByteArrayOutputStream and copies the bytes to the output, then calls toByteArray(). It handles large files by copying the bytes in blocks of 4KiB.
Safe solution (with capability of close streams correctly):
Java 9+:
final byte[] bytes;
try (inputStream) {
bytes = inputStream.readAllBytes();
}
Java 8:
public static byte[] readAllBytes(InputStream inputStream) throws IOException {
final int bufLen = 4 * 0x400; // 4KB
byte[] buf = new byte[bufLen];
int readLen;
IOException exception = null;
try {
try (ByteArrayOutputStream outputStream = new ByteArrayOutputStream()) {
while ((readLen = inputStream.read(buf, 0, bufLen)) != -1)
outputStream.write(buf, 0, readLen);
return outputStream.toByteArray();
}
} catch (IOException e) {
exception = e;
throw e;
} finally {
if (exception == null) inputStream.close();
else try {
inputStream.close();
} catch (IOException e) {
exception.addSuppressed(e);
}
}
}
Kotlin (when Java 9+ isn't accessible):
@Throws(IOException::class)
fun InputStream.readAllBytes(): ByteArray {
val bufLen = 4 * 0x400 // 4KB
val buf = ByteArray(bufLen)
var readLen: Int = 0
ByteArrayOutputStream().use { o ->
this.use { i ->
while (i.read(buf, 0, bufLen).also { readLen = it } != -1)
o.write(buf, 0, readLen)
}
return o.toByteArray()
}
}
To avoid nested use see here.
Scala (when Java 9+ isn't accessible) (By @Joan. Thx):
def readAllBytes(inputStream: InputStream): Array[Byte] =
Stream.continually(inputStream.read).takeWhile(_ != -1).map(_.toByte).toArray
The other case to get correct byte array via stream, after send request to server and waiting for the response.
/**
* Begin setup TCP connection to PC app
* to open integrate connection between mobile app and pc app (or mobile app)
*/
mSocket = new Socket(IP, port);
// mSocket.setSoTimeout(30000);
DataOutputStream mDos = new DataOutputStream(mSocket.getOutputStream());
String str = "MobileRequest#" + params[0] + "#<EOF>";
mDos.write(str.getBytes());
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
/* Since data are accepted as byte, all of them will be collected in the
following byte array which initialised with accepted data length. */
DataInputStream mDis = new DataInputStream(mSocket.getInputStream());
byte[] data = new byte[mDis.available()];
// Collecting data into byte array
for (int i = 0; i < data.length; i++)
data[i] = mDis.readByte();
// Converting collected data in byte array into String.
String RESPONSE = new String(data);
This is my copy-paste version:
@SuppressWarnings("empty-statement")
public static byte[] inputStreamToByte(InputStream is) throws IOException {
if (is == null) {
return null;
}
// Define a size if you have an idea of it.
ByteArrayOutputStream r = new ByteArrayOutputStream(2048);
byte[] read = new byte[512]; // Your buffer size.
for (int i; -1 != (i = is.read(read)); r.write(read, 0, i));
is.close();
return r.toByteArray();
}