Why doesn't Kotlin allow to use lateinit with primitive types?

前端 未结 3 1199
-上瘾入骨i
-上瘾入骨i 2020-11-29 05:32

In the Kotlin language we, by default, have to initialize each variable when it is introduced. To avoid this, the lateinit keyword can be used. Referring to a <

相关标签:
3条回答
  • 2020-11-29 06:23

    A short answer is that with primitives you can always use 0 as the default, and with nullable types null as a default. Only non-nullable non-primitive types may need lateinit to work around the type safety system.

    Actually, there is no need for initializing a variable in Kotlin as long as it has a value before the first access and it can be statically proved. Which means this code is perfectly valid:

    fun main(args: Array<String>) {
        var x: Int
        val y: Double
    
        x = 0
        y = x + 0.1
    
        println("$x, $y") 
    }
    

    But there are (rare) cases when the initialisation cannot be statically proved. The most common case is a class field which uses any form of dependency injection:

    class Window {
        @Inject lateinit parent: Parent
    }
    
    0 讨论(0)
  • 2020-11-29 06:25

    I think that in case of primitives it's less resources taking to simply initialise it to let me say 0 and hold the simple value in memory rather than store extra information about the object nullability which is used by lateinit mechanism.

    Correct me if it's not the case.

    0 讨论(0)
  • 2020-11-29 06:29

    For (non-nullable) object types, Kotlin uses the null value to mark that a lateinit property has not been initialized and to throw the appropriate exception when the property is accessed.

    For primitive types, there is no such value, so there is no way to mark a property as non-initialized and to provide the diagnostics that lateinit needs to provide. (We could try to use a separate marker of some kind, but that marker would not be updated when initializing the field through reflection, which is a major use case of lateinit).

    Therefore, lateinit is supported for properties of object types only.

    0 讨论(0)
提交回复
热议问题