How can I parse JSON into a html table using PHP?

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I have to get a table in my website. And have to get the data for this table from \"http://west.basketball.nl/db/json/stand.pl?szn_Naam=2014-2015&cmp_ID=373\" I\'ve trie

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北恋

2020-11-29 05:58

This code below can be useful for dynamically converting your entire table without having to define column names.

 echo "<table>";
        echo "<tr>";
        foreach(array_keys($your_array[0]) as $head){
            echo "<td>$head</td>";
        }
        echo "</tr>";

        foreach($your_array as $row){
            echo "<tr>";            
            foreach($row as $col){
                echo "<td>$col</td>";
            }
            echo "</tr>";
        }
        echo "</table>";

        return $posicoes;

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我在风中等你

2020-11-29 06:00
Why not try :
```
$data = json_decode($json, true);
```
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轻奢々

2020-11-29 06:05

If you want recursive way:

public static function jsonToDebug($jsonText = '')
{
    $arr = json_decode($jsonText, true);
    $html = "";
    if ($arr && is_array($arr)) {
        $html .= self::_arrayToHtmlTableRecursive($arr);
    }
    return $html;
}

private static function _arrayToHtmlTableRecursive($arr) {
    $str = "<table><tbody>";
    foreach ($arr as $key => $val) {
        $str .= "<tr>";
        $str .= "<td>$key</td>";
        $str .= "<td>";
        if (is_array($val)) {
            if (!empty($val)) {
                $str .= self::_arrayToHtmlTableRecursive($val);
            }
        } else {
            $str .= "<strong>$val</strong>";
        }
        $str .= "</td></tr>";
    }
    $str .= "</tbody></table>";

    return $str;
}

Then call echo YourClass::jsonToDebug($jsonText);

My test on http://sandbox.onlinephpfunctions.com/

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再見小時候

2020-11-29 06:18

Ok first thing to do when getting data from an external source is to understand what is being returned.

So do

<?php
$json=file_get_contents("http://west.basketball.nl/db/json/stand.pl?szn_Naam=2014-2015&cmp_ID=373");
$data =  json_decode($json);

print_r($data);

Result:

So now you know you are dealing with an OBJECT and not scalar values or an array.

So try this code:-

<?php
    $json=file_get_contents("http://west.basketball.nl/db/json/stand.pl?szn_Naam=2014-2015&cmp_ID=373");
    $data =  json_decode($json);

    if (count($data->stand)) {
        // Open the table
        echo "<table>";

        // Cycle through the array
        foreach ($data->stand as $idx => $stand) {

            // Output a row
            echo "<tr>";
            echo "<td>$stand->afko</td>";
            echo "<td>$stand->positie</td>";
            echo "</tr>";
        }

        // Close the table
        echo "</table>";
    }
?>

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名媛妹妹

2020-11-29 06:20

I guess, the issue is with the variables you are using - $afko and $positie. Please try with the below code -

// Cycle through the array
foreach ($data as $stand) {
    // Output a row
    echo "<tr>";
    echo "<td> . $stand['afko'] . </td>";
    echo "<td> . $stand['positie'] . </td>";
    echo "</tr>";
}

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