PHP pass function name as param then call the function?

Question

I need to pass a function as a parameter to another function and then call the passed function from within the function...This is probably easier for me to explain in code..

Answer 1

In php this is very simple.

<?php

function here() {
  print 'here';
}


function dynamo($name) {
 $name();
}

//Will work
dynamo('here');
//Will fail
dynamo('not_here');