I have two lists and I want to concatenate them element-wise. One of the list is subjected to string-formatting before concatenation.
For example :
Than can be done elegantly with map and zip:
map(lambda (x,y): x+y, zip(list1, list2))
Example:
In [1]: map(lambda (x,y): x+y, zip([1,2,3,4],[4,5,6,7]))
Out[1]: [5, 7, 9, 11]
inputs:
a = [0, 1, 5, 6, 10, 11]
b = ['asp1', 'asp1', 'asp1', 'asp1', 'asp2', 'asp2']
concat_func = lambda x,y: x + "" + str(y)
list(map(concat_func,b,a)) # list the map function
output:
['asp10', 'asp11', 'asp15', 'asp16', 'asp210', 'asp211']
If you wanted to concatenate arbitrary number of lists, you could do this:
In [1]: lists = [["a", "b", "c"], ["m", "n", "o"], ["p", "q", "r"]] # Or more
In [2]: lists
Out[2]: [['a', 'b', 'c'], ['m', 'n', 'o'], ['p', 'q', 'r']]
In [4]: list(map("".join, zip(*lists)))
Out[4]: ['amp', 'bnq', 'cor']
Use zip:
>>> ["{}{:02}".format(b_, a_) for a_, b_ in zip(a, b)]
['asp100', 'asp101', 'asp105', 'asp106', 'asp210', 'asp211']
not using zip. I dunno, I think this is the obvious way to do it. Maybe I just learnt C first :)
c=[]
for i in xrange(len(a)):
c.append("%s%02d" % (b[i],a[i]))
Other solution (preferring printf formating style over .format()
usage), it's also smaller:
>>> ["%s%02d" % t for t in zip(b, a)]
['asp100', 'asp101', 'asp105', 'asp106', 'asp210', 'asp211']