Check if input is number or letter javascript

Question

I\'m using forms in HTML and javascript. I would like an alert to pop up only if the user inputs a LETTER and clicks submit.

So I have

Answer 1

You could use the isNaN Function. It returns true if the data is not a number. That would be something like that:

function checkInp()
{
    var x=document.forms["myForm"]["age"].value;
    if (isNaN(x)) // this is the code I need to change
    {
        alert("Must input numbers");
        return false;
    }
}

Note: isNan considers 10.2 as a valid number.

Answer 2

You can use the isNaN function to determine if a value does not convert to a number. Example as below:

function checkInp()
{
  var x=document.forms["myForm"]["age"].value;
  if (isNaN(x)) 
  {
    alert("Must input numbers");
    return false;
  }
}

Answer 3

function isNumber(data){
    data = data +"e1";                      // Disallow eng. notation "10e2"+"e1" is NaN
    var clean = parseFloat(data,10) / data ; // 1 if parsed cleanly
    return ( data==0 || clean && (data/data) === 1.0);  // Checks for NaN
}

function isInteger(data){
    data = data +"e1";                      // Disallow eng. notation "10e2"+"e1" is NaN
    var clean = parseInt(data,10) / data ; // 1 if parsed cleanly
    return (data==0 ||clean && (data%1) === 0);          // Checks For integer and NaN
}

//Expected pass
console.log(isNumber("0"))
console.log(isNumber("-0.0"))
console.log(isNumber("+0.0"))
console.log(isNumber(0))
console.log(isNumber(-0.0))
console.log(isNumber(+0.0))
console.log(isNumber(1))
console.log(isNumber(-10.0))
console.log(isNumber(+1000.000001))
console.log(isNumber(1))
console.log(isNumber(-10.0))
console.log(isNumber(+1000.000001))

//Expected fail
console.log(isNumber("FF"))
console.log(isNumber("1e1"))
console.log(isNumber("seven"))

Answer 4

I think the easiest would be to create a Number object with the string and check if with the help of isInteger function provided by Number class itself.

Number.isInteger(Number('1')) //true
Number.isInteger(Number('1 mango')) //false
Number.isInteger(Number(1)) //true
Number.isInteger(Number(1.9)) //false

Answer 5

Try this:

if(parseInt("0"+x, 10) > 0){/* x is integer */}

Answer 6

A better(error-free) code would be like:

function isReallyNumber(data) {
    return typeof data === 'number' && !isNaN(data);
}

This will handle empty strings as well. Another reason, isNaN("12") equals to false but "12" is a string and not a number, so it should result to true. Lastly, a bonus link which might interest you.