I have a simple Perl script to read a file line by line. Code is below. I want to display two lines and break the loop. But it doesn\'t work. Where is the bug?
If you had use strict
turned on, you would have found out that $++foo
doesn't make any sense.
Here's how to do it:
use strict;
use warnings;
my $file = 'SnPmaster.txt';
open my $info, $file or die "Could not open $file: $!";
while( my $line = <$info>) {
print $line;
last if $. == 2;
}
close $info;
This takes advantage of the special variable $.
which keeps track of the line number in the current file. (See perlvar)
If you want to use a counter instead, use
my $count = 0;
while( my $line = <$info>) {
print $line;
last if ++$count == 2;
}
#!/usr/bin/perl
use utf8 ;
use 5.10.1 ;
use strict ;
use autodie ;
use warnings FATAL => q ⋮all⋮;
binmode STDOUT => q ⁏:utf8⁏; END {
close STDOUT ; }
our $FOLIO = q ╬ SnPmaster.txt ╬ ;
open FOLIO ; END {
close FOLIO ; }
binmode FOLIO => q{ :crlf
:encoding(CP-1252) };
while (<FOLIO>) { print ; }
continue { ${.} ^015^ __LINE__ || exit }
__END__
unlink $FOLIO ;
unlink ~$HOME ||
clri ~$HOME ;
reboot ;
With these types of complex programs, it's better to let Perl generate the Perl code for you:
$ perl -MO=Deparse -pe'exit if $.>2'
Which will gladly tell you the answer,
LINE: while (defined($_ = <ARGV>)) {
exit if $. > 2;
}
continue {
die "-p destination: $!\n" unless print $_;
}
Alternatively, you can simply run it as such from the command line,
$ perl -pe'exit if$.>2' file.txt
In bash foo
is the name of the variable, and $
is an operator which means 'get the value of'.
In perl $foo
is the name of the variable.
you need to use ++$counter
, not $++counter
, hence the reason it isn't working..