I use the following function
=DAYS360(A2, A35)
to calculate the difference between two dates in my column. However, the column is ever exp
To find the last non-empty cell you can use INDEX and MATCH functions like this:
=DAYS360(A2; INDEX(A:A; MATCH(99^99;A:A; 1)))
I think this is a little bit faster and easier.
Although the question is already answered, there is an eloquent way to do it.
Use just the column name to denote last non-empty row of that column.
For example:
If your data is in A1:A100
and you want to be able to add some more data to column A, say it can be A1:A105
or even A1:A1234
later, you can use this range:
A1:A
So to get last non-empty value in a range, we will use 2 functions:
The answer is =INDEX(B3:B,COUNTA(B3:B))
.
Here is the explanation:
COUNTA(range)
returns number of values in a range, we can use this to get the count of rows.
INDEX(range, row, col)
returns the value in a range at position row
and col
(col=1
if not specified)
Examples:
INDEX(A1:C5,1,1) = A1
INDEX(A1:C5,1) = A1 # implicitly states that col = 1
INDEX(A1:C5,1,2) = A2
INDEX(A1:C5,2,1) = B1
INDEX(A1:C5,2,2) = B2
INDEX(A1:C5,3,1) = C1
INDEX(A1:C5,3,2) = C2
For the picture above, our range will be B3:B
. So we will count how many values are there in range B3:B
by COUNTA(B3:B)
first. In the left side, it will produce 8
since there are 8 values while it will produce 9
in the right side. We also know that the last value is in the 1st column of the range B3:B
so the col
parameter of INDEX
must be 1 and the row
parameter should be COUNTA(B3:B)
.
PS: please upvote @bloodymurderlive's answer since he wrote it first, I'm just explaining it here.
I went a different route. Since I know I'll be adding something into a row/column one by one, I find out the last row by first counting the fields that have data. I'll demonstrate this with a column:
=COUNT(A5:A34)
So, let's say that returned 21. A5 is 4 rows down, so I need to get the 21st position from the 4th row down. I can do this using inderect, like so:
=INDIRECT("A"&COUNT(A5:A34)+4)
It's finding the amount of rows with data, and returning me a number I'm using as an index modifier.
If A2:A contains dates contiguously then INDEX(A2:A,COUNT(A2:A)) will return the last date. The final formula is
=DAYS360(A2,INDEX(A2:A,COUNT(A2:A)))