Regex to Match Symbols: !$%^&*()_+|~-=`{}[]:";'<>?,./

Question

I\'m trying to create a Regex test in JavaScript that will test a string to contain any of these characters:

!$%^&am         


        

Answer 1

A simple way to achieve this is the negative set [^\w\s]. This essentially catches:

• Anything that is not an alphanumeric character (letters and numbers)
• Anything that is not a space, tab, or line break (collectively referred to as whitespace)

For some reason [\W\S] does not work the same way, it doesn't do any filtering. A comment by Zael on one of the answers provides something of an explanation.

Answer 2

// The string must contain at least one special character, escaping reserved RegEx characters to avoid conflict
  const hasSpecial = password => {
    const specialReg = new RegExp(
      '^(?=.*[!@#$%^&*"\\[\\]\\{\\}<>/\\(\\)=\\\\\\-_´+`~\\:;,\\.€\\|])',
    );
    return specialReg.test(password);
  };

Answer 3

The most simple and shortest way to accomplish this:

/[^\p{L}\d\s@#]/u

Explanation

[^...] Match a single character not present in the list below

• \p{L} => matches any kind of letter from any language

• \d => matches a digit zero through nine

• \s => matches any kind of invisible character

• @# => @ and # characters

Don't forget to pass the u (unicode) flag.

Answer 4

Replace all latters from any language in 'A', and if you wish for example all digits to 0:

return str.replace(/[^\s!-@[-`{-~]/g, "A").replace(/\d/g, "0");

Answer 5

Answer

/[\W\S_]/

Explanation

This creates a character class removing the word characters, space characters, and adding back the underscore character (as underscore is a "word" character). All that is left is the special characters. Capital letters represent the negation of their lowercase counterparts.

\W will select all non "word" characters equivalent to [^a-zA-Z0-9_]
\S will select all non "whitespace" characters equivalent to [ \t\n\r\f\v]
_ will select "_" because we negate it when using the \W and need to add it back in

Answer 6

The regular expression for this is really simple. Just use a character class. The hyphen is a special character in character classes, so it needs to be first:

/[-!$%^&*()_+|~=`{}\[\]:";'<>?,.\/]/

You also need to escape the other regular expression metacharacters.

Edit: The hyphen is special because it can be used to represent a range of characters. This same character class can be simplified with ranges to this:

/[$-/:-?{-~!"^_`\[\]]/

There are three ranges. '$' to '/', ':' to '?', and '{' to '~'. the last string of characters can't be represented more simply with a range: !"^_`[].

Use an ACSII table to find ranges for character classes.