How do I get the max and min values from a set of numbers entered?

Question

Below is what I have so far:

I don\'t know how to exclude 0 as a min number though. The assignment asks for 0 to be the exit number so I need to have the lowest numb

Answer 1

You just need to keep track of a max value like this:

int maxValue = 0;

Then as you iterate through the numbers, keep setting the maxValue to the next value if it is greater than the maxValue:

if (value > maxValue) {
    maxValue = value;
}

Repeat in the opposite direction for minValue.

Answer 2

It is better

public class Main {

    public static void main(String[] args) {

        System.out.print("Enter numbers: ");
        Scanner input = new Scanner(System.in);

        double max = Double.MIN_VALUE;
        double min = Double.MAX_VALUE;

        while (true) {

            if ( !input.hasNextDouble())
                break;

            Double num = input.nextDouble();

            min = Math.min(min, num);
            max = Math.max(max, num);

        }
        System.out.println("Max is: " + max);
        System.out.println("Min is: " + min);
    }
}

Answer 3

I tried to optimize solution by handling user input exceptions.

public class Solution {
    private static Integer TERMINATION_VALUE = 0;
    public static void main(String[] args) {
        Integer value = null;
        Integer minimum = Integer.MAX_VALUE;
        Integer maximum = Integer.MIN_VALUE;
        Scanner scanner = new Scanner(System.in);
        while (value != TERMINATION_VALUE) {
            Boolean inputValid = Boolean.TRUE;
            try {
                System.out.print("Enter a value: ");
                value = scanner.nextInt();
            } catch (InputMismatchException e) {
                System.out.println("Value must be greater or equal to " + Integer.MIN_VALUE + " and less or equals to " + Integer.MAX_VALUE );
                inputValid = Boolean.FALSE;
                scanner.next();
            }
            if(Boolean.TRUE.equals(inputValid)){
                minimum = Math.min(minimum, value);
                maximum = Math.max(maximum, value);
            }
        }
        if(TERMINATION_VALUE.equals(minimum) || TERMINATION_VALUE.equals(maximum)){
            System.out.println("There is not any valid input.");
        } else{
            System.out.println("Minimum: " + minimum);
            System.out.println("Maximum: " + maximum);
        }
        scanner.close();
    }
}

Answer 4

Here's a possible solution:

public class NumInput {
  public static void main(String [] args) {
    int min = Integer.MAX_VALUE;
    int max = Integer.MIN_VALUE;

    Scanner s = new Scanner(System.in);
    while (true) {
      System.out.print("Enter a Value: ");
      int val = s.nextInt();

      if (val == 0) {
          break;
      }
      if (val < min) {
          min = val;
      }
      if (val > max) {
         max = val;
      }
    }

    System.out.println("min: " + min);
    System.out.println("max: " + max);
  }
}

(not sure about using int or double thought)

Answer 5

//for excluding zero
public class SmallestInt {

    public static void main(String[] args) {

        Scanner input= new Scanner(System.in);

        System.out.println("enter number");
        int val=input.nextInt();
        int min=val;

        //String notNull;

        while(input.hasNextInt()==true)
        {
            val=input.nextInt();
            if(val<min)
                min=val;
        }
        System.out.println("min is: "+min);
    }
}

Answer 6

This is what I did and it works try and play around with it. It calculates total,avarage,minimum and maximum.

public static void main(String[] args) {
   int[] score= {56,90,89,99,59,67};
   double avg;
   int sum=0;
   int maxValue=0;
   int minValue=100;

   for(int i=0;i<6;i++){
       sum=sum+score[i];
   if(score[i]<minValue){
    minValue=score[i];
   }
   if(score[i]>maxValue){
    maxValue=score[i];
   }
   }
   avg=sum/6.0;
System.out.print("Max: "+maxValue+"," +" Min: "+minValue+","+" Avarage: "+avg+","+" Sum: "+sum);}

 }