printf %f with only 2 numbers after the decimal point?

Question

In my printf, I need to use %f but I\'m not sure how to truncate to 2 decimal places:

Example: getting

3.14159

Answer 1

I suggest to learn it with printf because for many cases this will be sufficient for your needs and you won't need to create other objects.

double d = 3.14159;     
printf ("%.2f", d);

But if you need rounding please refer to this post

https://stackoverflow.com/a/153785/2815227

Answer 2

as described in Formatter class, you need to declare precision. %.2f in your case.

Answer 3

Use this:

printf ("%.2f", 3.14159);

Answer 4

You can try printf("%.2f", [double]);

Answer 5

Try:

printf("%.2f", 3.14159);

Reference:

http://www.cplusplus.com/reference/clibrary/cstdio/printf/

Answer 6

You can use something like this:

printf("%.2f", number);

If you need to use the string for something other than printing out, use the NumberFormat class:

NumberFormat formatter = new DecimalFormatter("#.##");
String s = formatter.format(3.14159265); // Creates a string containing "3.14"