Sort Dictionary by Key Value

Question

let dict: [String:Int] = [\"apple\":5, \"pear\":9, \"grape\":1]

How do you sort the dictionary based on the Int value so that the outp

Answer 1

You need to sort your dictionary values, not your keys. You can create an array of tuples from your dictionary sorting it by its values as follow:

Xcode 9 • Swift 4 or Xcode 8 • Swift 3

let fruitsDict = ["apple": 5, "pear": 9, "grape": 1]
let fruitsTupleArray = fruitsDict.sorted{ $0.value > $1.value }

fruitsTupleArray // [(.0 "pear", .1 9), (.0 "apple", .1 5), (.0 "grape", .1 1)]

for (fruit,votes) in fruitsTupleArray {
    print(fruit,votes)
}

fruitsTupleArray.first?.key   // "pear"
fruitsTupleArray.first?.value   // 9

---

To sort your dictionary using your keys

let fruitsTupleArray = fruitsDict.sorted{ $0.key > $1.key }
fruitsTupleArray  // [(key "pear", value 9), (key "grape", value 1), (key "apple", value 5)]

To sort your dictionary using its keys and localized comparison:

let fruitsTupleArray = fruitsDict.sorted { $0.key.localizedCompare($1.key) == .orderedAscending  }

Answer 2

Dictionaries can't be sorted. Generally, when I need things sorted from a dictionary, I will make a separate array of my dictionary keys.

In your case, make an array of the keys, sort them by comparing their values in the dictionary.

Answer 3

It can be achieved by using the below implementation

let sortedDictionary = unsortedDictionary.sorted{$0.key > $1.key}