C# with MySQL INSERT parameters

Question

Good day to all, I\'m using Visual C# 2010 and MySQL Version 5.1.48-community. I hope you can help me with this code. I don\'t find it working on me. What am I missing?

Answer 1

Use the AddWithValue method:

comm.Parameters.AddWithValue("@person", "Myname");
comm.Parameters.AddWithValue("@address", "Myaddress");

Answer 2

You may use AddWithValue method like:

string connString = ConfigurationManager.ConnectionStrings["default"].ConnectionString;
MySqlConnection conn = new MySqlConnection(connString);
conn.Open();
MySqlCommand comm = conn.CreateCommand();
comm.CommandText = "INSERT INTO room(person,address) VALUES(@person, @address)";
comm.Parameters.AddWithValue("@person", "Myname");
comm.Parameters.AddWithValue("@address", "Myaddress");
comm.ExecuteNonQuery();
conn.Close();

OR

Try with ? instead of @, like:

string connString = ConfigurationManager.ConnectionStrings["default"].ConnectionString;
MySqlConnection conn = new MySqlConnection(connString);
conn.Open();
MySqlCommand comm = conn.CreateCommand();
comm.CommandText = "INSERT INTO room(person,address) VALUES(?person, ?address)";
comm.Parameters.Add("?person", "Myname");
comm.Parameters.Add("?address", "Myaddress");
comm.ExecuteNonQuery();
conn.Close();

Hope it helps...

Answer 3

try this it is working

 MySqlCommand dbcmd = _conn.CreateCommand();
    dbcmd.CommandText = sqlCommandString;
    dbcmd.ExecuteNonQuery();
    long imageId = dbcmd.LastInsertedId;

Answer 4

comm.Parameters.Add("person", "Myname");

Answer 5

What I did is like this.

String person;
String address;
person = your value;
address =your value;
string connString = ConfigurationManager.ConnectionStrings["default"].ConnectionString;
    MySqlConnection conn = new MySqlConnection(connString);
    conn.Open();
    MySqlCommand comm = conn.CreateCommand();
    comm.CommandText = "INSERT INTO room(person,address) VALUES('"+person+"','"+address+"')";
    comm.ExecuteNonQuery();
    conn.Close();

Answer 6

Three things: use the using statement, use AddWithValue and prefix parameters with ? and add Allow User Variables=True to the connection string.

 string connString = ConfigurationManager.ConnectionStrings["default"].ConnectionString;
 using (var conn = new MySqlConnection(connString))
 {
      conn.Open();
      var comm = conn.CreateCommand();
      comm.CommandText = "INSERT INTO room(person,address) VALUES(@person, @address)";
      comm.Parameters.AddWithValue("?person", "Myname");
      comm.Parameters.AddWithValue("?address", "Myaddress");
      comm.ExecuteNonQuery();
  }

Also see http://msdn.microsoft.com/en-us/library/system.data.sqlclient.sqlcommand.parameters.aspx for more information about the command usage, and http://dev.mysql.com/doc/refman/5.1/en/connector-net-connection-options.html for information about the Allow User Variables option (only supported in version 5.2.2 and above).