How do I do a “NOT IN” query in Mongo?

Question

This is my document:

{ 
    title:\"Happy thanksgiving\",
    body: \"come over for dinner\",
    blocked:[
       {user:333, name:\'john\'},
       {user:99         


        

Answer 1

Since you are comparing against a single value, your example actually doesn't need a NOT IN operation. This is because Mongo will apply its search criteria to every element of an array subdocument. You can use the NOT EQUALS operator, $ne, to get what you want as it takes the value that cannot turn up in the search:

db.myCollection.find({'blocked.user': {$ne: 11}});

However if you have many things that it cannot equal, that is when you would use the NOT IN operator, which is $nin. It takes an array of values that cannot turn up in the search:

db.myCollection.find({'blocked.user': {$nin: [11, 12, 13]}});

Answer 2

You can use $in or $nin for "not in"

Example ...

> db.people.find({ crowd : { $nin: ["cool"] }});

I put a bunch more examples here: http://learnmongo.com/posts/being-part-of-the-in-crowd/

Answer 3

See http://docs.mongodb.org/manual/reference/operator/query/nin/#op._S_nin

db.inventory.find( { qty: { $nin: [ 5, 15 ] } } )

This query will select all documents in the inventory collection where the qty field value does not equal 5 nor 15. The selected documents will include those documents that do not contain the qty field.

If the field holds an array, then the $nin operator selects the documents whose field holds an array with no element equal to a value in the specified array (e.g. , , etc.).

Answer 4

Try the following:

db.stack.find({"blocked.user":{$nin:[11]}})

This worked for me.