How do I get difference between two dates in android?, tried every thing and post

Question

I saw all the post in here and still I can\'t figure how do get difference between two android dates.

This is what I do:

long diff = date1.getTime()          


        

Answer 1

You're close to the right answer, you are getting the difference in milliseconds between those two dates, but when you attempt to construct a date out of that difference, it is assuming you want to create a new Date object with that difference value as its epoch time. If you're looking for a time in hours, then you would simply need to do some basic arithmetic on that diff to get the different time parts.

Java:

long diff = date1.getTime() - date2.getTime();
long seconds = diff / 1000;
long minutes = seconds / 60;
long hours = minutes / 60;
long days = hours / 24;

Kotlin:

val diff: Long = date1.getTime() - date2.getTime()
val seconds = diff / 1000
val minutes = seconds / 60
val hours = minutes / 60
val days = hours / 24

All of this math will simply do integer arithmetic, so it will truncate any decimal points

Answer 2

If you use Kotlin language for Android development, you can use ExperimentalTime extension. To get difference in days you can use it like this:

@ExperimentalTime
fun daysDiff(c1: Calendar, c2: Calendar): Double {
    val diffInMillis = c1.timeInMillis - c2.timeInMillis
    return diffInMillis.milliseconds.inDays
}

or if you want to get results as integer:

@ExperimentalTime
fun daysDiff2(c1: Calendar, c2: Calendar): Int {
    val diffInMillis = c1.timeInMillis - c2.timeInMillis
    return diffInMillis.milliseconds.toInt(DurationUnit.DAYS)
}

Answer 3

Here is my answer based on @Ole V. V. answer.

This also works with Singular.

private String getDuration(Date d1, Date d2) {
    Duration diff = Duration.between(d1.toInstant(), d2.toInstant());


    long days = diff.toDays();
    diff = diff.minusDays(days);
    long hours = diff.toHours();
    diff = diff.minusHours(hours);
    long minutes = diff.toMinutes();
    diff = diff.minusMinutes(minutes);
    long seconds = diff.toMillis();

    StringBuilder formattedDiff = new StringBuilder();
    if(days!=0){
        if(days==1){
            formattedDiff.append(days + " Day ");

        }else {
            formattedDiff.append(days + " Days ");
        }
    }if(hours!=0){
        if(hours==1){
            formattedDiff.append(hours + " hour ");
        }else{
            formattedDiff.append(hours + " hours ");
        }
    }if(minutes!=0){
        if(minutes==1){
            formattedDiff.append(minutes + " minute ");
        }else{
            formattedDiff.append(minutes + " minutes ");
        }
    }if(seconds!=0){
        if(seconds==1){
            formattedDiff.append(seconds + " second ");
        }else{
            formattedDiff.append(seconds + " seconds ");
        }
    }


    return formattedDiff.toString();
}

It works with a StringBuilder to append everything together.

Answer 4

Using georgian calander

 public void dateDifferenceExample() {

        // Set the date for both of the calendar instance
        GregorianCalendar calDate = new GregorianCalendar(2012, 10, 02,5,23,43);
        GregorianCalendar cal2 = new GregorianCalendar(2015, 04, 02);

        // Get the represented date in milliseconds
        long millis1 = calDate.getTimeInMillis();
        long millis2 = cal2.getTimeInMillis();

        // Calculate difference in milliseconds
        long diff = millis2 - millis1;

        // Calculate difference in seconds
        long diffSeconds = diff / 1000;

        // Calculate difference in minutes
        long diffMinutes = diff / (60 * 1000);

        // Calculate difference in hours
        long diffHours = diff / (60 * 60 * 1000);

        // Calculate difference in days
        long diffDays = diff / (24 * 60 * 60 * 1000);
    Toast.makeText(getContext(), ""+diffSeconds, Toast.LENGTH_SHORT).show();


}

Answer 5

I tried this method..but don't know why I am not getting proper result

long diff = date1.getTime() - date2.getTime();
long seconds = diff / 1000;
long minutes = seconds / 60;
long hours = minutes / 60;
long days = hours / 24;

But this works

long miliSeconds = date1.getTime() -date2.getTime();
long seconds = TimeUnit.MILLISECONDS.toSeconds(miliSeconds);
long minute = seconds/60;
long hour = minute/60;
long days = hour/24;

Answer 6

    long diffInMillisec = date1.getTime() - date2.getTime();

    long diffInDays = TimeUnit.MILLISECONDS.toDays(diffInMillisec);
    long diffInHours = TimeUnit.MILLISECONDS.toHours(diffInMillisec);
    long diffInMin = TimeUnit.MILLISECONDS.toMinutes(diffInMillisec);
    long diffInSec = TimeUnit.MILLISECONDS.toSeconds(diffInMillisec);