PHP: Read Specific Line From File

Question

I\'m trying to read a specific line from a text file using php. Here\'s the text file:

foo  
foo2

How would I get the content of the seco

Answer 1

I like daggett answer but there is another solution you can get try if your file is not big enough.

$file = __FILE__; // Let's take the current file just as an example.

$start_line = __LINE__ -1; // The same with the line what we look for. Take the line number where $line variable is declared as the start.

$lines_to_display = 5; // The number of lines to display. Displays only the $start_line if set to 1. If $lines_to_display argument is omitted displays all lines starting from the $start_line.

echo implode('', array_slice(file($file), $start_line, lines_to_display));

Answer 2

$myFile = "4-21-11.txt";
$fh = fopen($myFile, 'r');
while(!feof($fh))
{
    $data[] = fgets($fh);  
    //Do whatever you want with the data in here
    //This feeds the file into an array line by line
}
fclose($fh);

Answer 3

Use stream_get_line: stream_get_line — Gets line from stream resource up to a given delimiter Source: http://php.net/manual/en/function.stream-get-line.php

Answer 4

I would use the SplFileObject class...

$file = new SplFileObject("filename");
if (!$file->eof()) {
     $file->seek($lineNumber);
     $contents = $file->current(); // $contents would hold the data from line x
}

Answer 5

If you wanted to do it that way...

$line = 0;

while (($buffer = fgets($fh)) !== FALSE) {
   if ($line == 1) {
       // This is the second line.
       break;
   }   
   $line++;
}

Alternatively, open it with file() and subscript the line with [1].

Answer 6

If you use PHP on Linux, you may try the following to read text for example between 74th and 159th lines:

$text = shell_exec("sed -n '74,159p' path/to/file.log");

This solution is good if your file is large.