Accept function as parameter in PHP

Question

I\'ve been wondering whether is possible or not to pass a function as parameter in PHP; I want something like when you\'re programming in JS:

object.exampleM         


        

Answer 1

PHP VERSION >= 5.3.0

Example 1: basic

function test($test_param, $my_function) {
    return $my_function($test_param);
}

test("param", function($param) {
    echo $param;
}); //will echo "param"

Example 2: std object

$obj = new stdClass();
$obj->test = function ($test_param, $my_function) {
    return $my_function($test_param);
};

$test = $obj->test;
$test("param", function($param) {
    echo $param;
});

Example 3: non static class call

class obj{
    public function test($test_param, $my_function) {
        return $my_function($test_param);
    }
}

$obj = new obj();
$obj->test("param", function($param) {
    echo $param;
});

Example 4: static class call

class obj {
    public static function test($test_param, $my_function) {
        return $my_function($test_param);
    }
}

obj::test("param", function($param) {
    echo $param;
});

Answer 2

According to @zombat's answer, it's better to validate the Anonymous Functions first:

function exampleMethod($anonFunc) {
    //execute anonymous function
    if (is_callable($anonFunc)) {
        $anonFunc();
    }
}

Or validate argument type since PHP 5.4.0:

function exampleMethod(callable $anonFunc) {}