C++11: Compile Time Calculation of Array

Question

Suppose I have some constexpr function f:

constexpr int f(int x) { ... }

And I have some const int N known at compile time:

Either<

Answer 1

If you want the array to live in static memory, you could try this:

template<class T> struct id { typedef T type; };
template<int...> struct int_pack {};
template<int N, int...Tail> struct make_int_range
    : make_int_range<N-1,N-1,Tail...> {};
template<int...Tail> struct make_int_range<0,Tail...>
    : id<int_pack<Tail...>> {};

#include <array>

constexpr int f(int n) { return n*(n+1)/2; }

template<class Indices = typename make_int_range<10>::type>
struct my_lookup_table;
template<int...Indices>
struct my_lookup_table<int_pack<Indices...>>
{
    static const int size = sizeof...(Indices);
    typedef std::array<int,size> array_type;
    static const array_type& get()
    {
        static const array_type arr = {{f(Indices)...}};
        return arr;
    }
};

#include <iostream>

int main()
{
    auto& lut = my_lookup_table<>::get();
    for (int i : lut)
        std::cout << i << std::endl;
}

If you want a local copy of the array to work on, simply remove the ampersand.