Given an NSArray
of NSDictionary
objects (containing similar objects and keys) is it possible to write perform a map to an array of specified key?
To summarize all other answers:
Ruby (as in the question):
array.map{|o| o.name}
Obj-C (with valueForKey):
[array valueForKey:@"name"];
Obj-C (with valueForKeyPath
, see KVC Collection Operators):
[array valueForKeyPath:@"[collect].name"];
Obj-C (with enumerateObjectsUsingBlock):
NSMutableArray *newArray = [NSMutableArray array];
[array enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
[newArray addObject:[obj name]];
}];
Swift (with map, see closures)
array.map { $0.name }
And, there are a couple of libraries that allow you to handle arrays in a more functional way. CocoaPods is recommended to install other libraries.
There is a special key-path operator for this: @unionOfObjects
. Probably it replaced [collect]
from previous versions.
Imagine a Transaction
class with payee
property:
NSArray *payees = [self.transactions valueForKeyPath:@"@unionOfObjects.payee"];
Apple docs on Array Operators in Key-Value coding.
It only saves a couple lines, but I use a category on NSArray. You need to ensure your block never returns nil, but other than that it's a time saver for cases where -[NSArray valueForKey:]
won't work.
@interface NSArray (Map)
- (NSArray *)mapObjectsUsingBlock:(id (^)(id obj, NSUInteger idx))block;
@end
@implementation NSArray (Map)
- (NSArray *)mapObjectsUsingBlock:(id (^)(id obj, NSUInteger idx))block {
NSMutableArray *result = [NSMutableArray arrayWithCapacity:[self count]];
[self enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
[result addObject:block(obj, idx)];
}];
return result;
}
@end
Usage is much like -[NSArray enumerateObjectsWithBlock:]
:
NSArray *people = @[
@{ @"name": @"Bob", @"city": @"Boston" },
@{ @"name": @"Rob", @"city": @"Cambridge" },
@{ @"name": @"Robert", @"city": @"Somerville" }
];
// per the original question
NSArray *names = [people mapObjectsUsingBlock:^(id obj, NSUInteger idx) {
return obj[@"name"];
}];
// (Bob, Rob, Robert)
// you can do just about anything in a block
NSArray *fancyNames = [people mapObjectsUsingBlock:^(id obj, NSUInteger idx) {
return [NSString stringWithFormat:@"%@ of %@", obj[@"name"], obj[@"city"]];
}];
// (Bob of Boston, Rob of Cambridge, Robert of Somerville)
@implementation NSArray (BlockRockinBeats)
- (NSArray*)mappedWithBlock:(id (^)(id obj, NSUInteger idx))block {
NSMutableArray* result = [NSMutableArray arrayWithCapacity:self.count];
[self enumerateObjectsUsingBlock:^(id currentObject, NSUInteger index, BOOL *stop) {
id mappedCurrentObject = block(currentObject, index);
if (mappedCurrentObject)
{
[result addObject:mappedCurrentObject];
}
}];
return result;
}
@end
I'm no Ruby expert so I'm not 100% confident I'm answering correctly, but based on the interpretation that 'map' does something to everything in the array and produces a new array with the results, I think what you probably want is something like:
NSMutableArray *replacementArray = [NSMutableArray array];
[existingArray enumerateObjectsUsingBlock:
^(NSDictionary *dictionary, NSUInteger idx, BOOL *stop)
{
NewObjectType *newObject = [something created from 'dictionary' somehow];
[replacementArray addObject:newObject];
}
];
So you're using the new support for 'blocks' (which are closures in more general parlance) in OS X 10.6/iOS 4.0 to perform the stuff in the block on everything in the array. You're choosing to do some operation and then add the result to a separate array.
If you're looking to support 10.5 or iOS 3.x, you probably want to look into putting the relevant code into the object and using makeObjectsPerformSelector: or, at worst, doing a manual iteration of the array using for(NSDictionary *dictionary in existingArray)
.