Django 1.11 Annotating a Subquery Aggregate

后端 未结 6 847
醉酒成梦
醉酒成梦 2020-11-28 04:22

This is a bleeding-edge feature that I\'m currently skewered upon and quickly bleeding out. I want to annotate a subquery-aggregate onto an existing queryset. Doing this bef

相关标签:
6条回答
  • 2020-11-28 04:39

    It's also possible to create a subclass of Subquery, that changes the SQL it outputs. For instance, you can use:

    class SQCount(Subquery):
        template = "(SELECT count(*) FROM (%(subquery)s) _count)"
        output_field = models.IntegerField()
    

    You then use this as you would the original Subquery class:

    spaces = Space.objects.filter(carpark=OuterRef('pk')).values('pk')
    Carpark.objects.annotate(space_count=SQCount(spaces))
    

    You can use this trick (at least in postgres) with a range of aggregating functions: I often use it to build up an array of values, or sum them.

    0 讨论(0)
  • 2020-11-28 04:41

    "works for me" doesn't help very much. But. I tried your example on some models I had handy (the Book -> Author type), it works fine for me in django 1.11b1.

    Are you sure you're running this in the right version of Django? Is this the actual code you're running? Are you actually testing this not on carpark but some more complex model?

    Maybe try to print(thequery.query) to see what SQL it's trying to run in the database. Below is what I got with my models (edited to fit your question):

    SELECT (SELECT COUNT(U0."id") AS "c"
    FROM "carparks_spaces" U0
    WHERE U0."carpark_id" = ("carparks_carpark"."id")
    GROUP BY U0."carpark_id") AS "space_count" FROM "carparks_carpark"
    

    Not really an answer, but hopefully it helps.

    0 讨论(0)
  • 2020-11-28 04:43

    I just bumped into a VERY similar case, where I had to get seat reservations for events where the reservation status is not cancelled. After trying to figure the problem out for hours, here's what I've seen as the root cause of the problem:

    Preface: this is MariaDB, Django 1.11.

    When you annotate a query, it gets a GROUP BY clause with the fields you select (basically what's in your values() query selection). After investigating with the MariaDB command line tool why I'm getting NULLs or Nones on the query results, I've came to the conclusion that the GROUP BY clause will cause the COUNT() to return NULLs.

    Then, I started diving into the QuerySet interface to see how can I manually, forcibly remove the GROUP BY from the DB queries, and came up with the following code:

    from django.db.models.fields import PositiveIntegerField
    
    reserved_seats_qs = SeatReservation.objects.filter(
            performance=OuterRef(name='pk'), status__in=TAKEN_TYPES
        ).values('id').annotate(
            count=Count('id')).values('count')
    # Query workaround: remove GROUP BY from subquery. Test this
    # vigorously!
    reserved_seats_qs.query.group_by = []
    
    performances_qs = Performance.objects.annotate(
        reserved_seats=Subquery(
            queryset=reserved_seats_qs,
            output_field=PositiveIntegerField()))
    
    print(performances_qs[0].reserved_seats)
    

    So basically, you have to manually remove/update the group_by field on the subquery's queryset in order for it to not have a GROUP BY appended on it on execution time. Also, you'll have to specify what output field the subquery will have, as it seems that Django fails to recognize it automatically, and raises exceptions on the first evaluation of the queryset. Interestingly, the second evaluation succeeds without it.

    I believe this is a Django bug, or an inefficiency in subqueries. I'll create a bug report about it.

    Edit: the bug report is here.

    0 讨论(0)
  • 2020-11-28 04:47

    If I understand correctly, you are trying to count Spaces available in a Carpark. Subquery seems overkill for this, the good old annotate alone should do the trick:

    Carpark.objects.annotate(Count('spaces'))
    

    This will include a spaces__count value in your results.


    OK, I have seen your note...

    I was also able to run your same query with other models I had at hand. The results are the same, so the query in your example seems to be OK (tested with Django 1.11b1):

    activities = Activity.objects.filter(event=OuterRef('pk')).values('event')
    count_activities = activities.annotate(c=Count('*')).values('c')
    Event.objects.annotate(spaces__count=Subquery(count_activities))
    

    Maybe your "simplest real-world example" is too simple... can you share the models or other information?

    0 讨论(0)
  • 2020-11-28 04:52

    A solution which would work for any general aggregation could be implemented using Window classes from Django 2.0. I have added this to the Django tracker ticket as well.

    This allows the aggregation of annotated values by calculating the aggregate over partitions based on the outer query model (in the GROUP BY clause), then annotating that data to every row in the subquery queryset. The subquery can then use the aggregated data from the first row returned and ignore the other rows.

    Performance.objects.annotate(
        reserved_seats=Subquery(
            SeatReservation.objects.filter(
                performance=OuterRef(name='pk'),
                status__in=TAKEN_TYPES,
            ).annotate(
                reserved_seat_count=Window(
                    expression=Count('pk'),
                    partition_by=[F('performance')]
                ),
            ).values('reserved_seat_count')[:1],
            output_field=FloatField()
        )
    )
    
    0 讨论(0)
  • 2020-11-28 04:55

    Shazaam! Per my edits, an additional column was being output from my subquery. This was to facilitate ordering (which just isn't required in a COUNT).

    I just needed to remove the prescribed meta-order from the model. You can do this by just adding an empty .order_by() to the subquery. In my code terms that meant:

    spaces = Space.objects.filter(carpark=OuterRef('pk')).order_by().values('carpark')
    count_spaces = spaces.annotate(c=Count('*')).values('c')
    Carpark.objects.annotate(space_count=Subquery(count_spaces))
    

    And that works. Superbly. So annoying.

    0 讨论(0)
提交回复
热议问题