Remove multiple objects with rm()

Question

My memory is getting clogged by a bunch of intermediate files (call them temp1, temp2, etc). Is it possible to remove them from memory without doing rm(temp1),

Answer 1

Another variation you can try is(expanding @mnel's answer) if you have many temp'x'.

here "n" could be the number of temp variables present

rm(list = c(paste("temp",c(1:n),sep="")))

Answer 2

An other solution rm(list=ls(pattern="temp")), remove all objects matching the pattern.

Answer 3

Or using regular expressions

"rmlike" <- function(...) {
  names <- sapply(
    match.call(expand.dots = FALSE)$..., as.character)
  names = paste(names,collapse="|")
  Vars <- ls(1)
  r <- Vars[grep(paste("^(",names,").*",sep=""),Vars)]
  rm(list=r,pos=1)
}

rmlike(temp)

Answer 4

Make the list a character vector (not a vector of names)

rm(list = c('temp1','temp2'))

or

rm(temp1, temp2)