I have a application where I want to show different locations (one at the time, picked by user input) by launching Google Maps with their specific geo coordinates.
I
Double myLatitude = 44.433106;
Double myLongitude = 26.103687;
String labelLocation = "Jorgesys @ Bucharest";
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("geo:<" + myLatitude + ">,<" + myLongitude + ">?q=<" + myLatitude + ">,<" + myLongitude + ">(" + labelLocation + ")"));
startActivity(intent);
String urlAddress = "http://maps.google.com/maps?q="+ myLatitude +"," + myLongitude +"("+ labelLocation + ")&iwloc=A&hl=es";
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(urlAddress));
startActivity(intent);
String urlAddress = "http://maps.googleapis.com/maps/api/streetview?size=500x500&location=" + myLatitude + "," + myLongitude + "&fov=90&heading=235&pitch=10&sensor=false";
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(urlAddress));
startActivity(intent);
The accepted answer is correct, except when your label has an ampersand (&) in it.
Looking at A Uniform Resource Identifier for Geographic Locations ('geo' URI):
Section 5.1 states:
if the final URI is to include a 'query' component, add the component delimiter "?" to the end of the result, followed by the encoded query string.
Unfortunately for us, doing this will also escape the '=' which is not what we want.
We should do this:
String label = "Cinnamon & Toast";
String uriBegin = "geo:12,34";
String query = "12,34(" + label + ")";
String encodedQuery = Uri.encode(query);
String uriString = uriBegin + "?q=" + encodedQuery;
Uri uri = Uri.parse(uriString);
Intent intent = new Intent(android.content.Intent.ACTION_VIEW, uri);
startActivity(intent);
Try appending (LocationMarkerName) to the geo: uri. For example, "geo:,?z=17(LocationMarkerName)"
In Google Maps on Android searching for 23.0980,30.6797 (NamedMarker), it seems to centre the map and position a marker with name NamedMarker at that position.
This string works well for me:
String geoUriString="geo:"+lat+","+lon+"?q=("+head+")@"+lat+","+lon;
Uri geoUri = Uri.parse(geoUriString);
Log.e(TAG, "String: "+geoUriString);
Intent mapCall = new Intent(Intent.ACTION_VIEW, geoUri);
startActivity(mapCall);
I just confirmed the following snippet from @Kenton Price still works on Android 4.4 (KitKat):
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("geo:<lat>,<long>?q=<lat>,<long>(Label+Name)"));
startActivity(intent);
Try this:
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("geo:<lat>,<long>?q=<lat>,<long>(Label+Name)"));
startActivity(intent);
You can omit (Label+Name) if you don't want a label, and it will choose one randomly based on the nearest street or other thing it thinks relevant.