Extract value of attribute node via XPath

Question

How can I extract the value of an attribute node via XPath?

A sample XML file is:

Answer 1

//Parent/Children[@  Attribute='value']/@Attribute

This is the case which can be used where element is having 2 attribute and we can get the one attribute with the help of another one.

Answer 2

You should use //Parent[@id='1']/Children/child/data(@name)

The attributes can not be serialized so you can't return them in an xml looking result. What you need to do is obtain the data from the attribute using data() function.

Answer 3

for all xml with namespace use local-name()

//*[local-name()='Parent'][@id='1']/*[local-name()='Children']/*[local-name()='child']/@name 

Answer 4

As answered above:

//Parent[@id='1']/Children/child/@name 

will only output the name attribute of the 4 child nodes belonging to the Parent specified by its predicate [@id=1]. You'll then need to change the predicate to [@id=2] to get the set of child nodes for the next Parent.

However, if you ignore the Parent node altogether and use:

//child/@name

you can select name attribute of all child nodes in one go.

name="Child_2"
name="Child_4"
name="Child_1"
name="Child_3"
name="Child_1"
name="Child_2"
name="Child_4"
name="Child_3"

Answer 5

@ryenus, You need to loop through the result. This is how I'd do it in vbscript;

Set xmlDoc = CreateObject("Msxml2.DOMDocument")
xmlDoc.setProperty "SelectionLanguage", "XPath"
xmlDoc.load("kids.xml")

'Remove the id=1 attribute on Parent to return all child names for all Parent nodes
For Each c In xmlDoc.selectNodes ("//Parent[@id='1']/Children/child/@name")
    Wscript.Echo c.text
Next

Answer 6

//Parent[@id='1']/Children/child/@name 

Your original child[@name] means an element child which has an attribute name. You want child/@name.