How to get the path of src/test/resources directory in JUnit?

Question

I know I can load a file from src/test/resources with:

getClass().getResource(\"somefile\").getFile()

But how can I get the full path to th

Answer 1

I have a Maven3 project using JUnit 4.12 and Java8. In order to get the path of a file called myxml.xml under src/test/resources, I do this from within the test case:

@Test
public void testApp()
{
    File inputXmlFile = new File(this.getClass().getResource("/myxml.xml").getFile());
    System.out.println(inputXmlFile.getAbsolutePath());
    ...
}

Tested on Ubuntu 14.04 with IntelliJ IDE. Reference here.

Answer 2

If it's a spring project, we can use the below code to get files from src/test/resource folder.

File file = ResourceUtils.getFile(this.getClass().getResource("/some_file.txt"));

Answer 3

With Spring, you can use this:

import org.springframework.core.io.ClassPathResource;

// Don't worry when use a not existed directory or a empty directory
// It can be used in @before
String dir = new ClassPathResource(".").getFile().getAbsolutePath()+"/"+"Your Path";

Answer 4

With Spring you could easily read it from the resources folder (either main/resources or test/resources):

For example create a file: test/resources/subfolder/sample.json

@Test
public void testReadFile() {
    String json = this.readFile("classpath:subfolder/sample.json");
    System.out.println(json);
}

public String readFile(String path) {
    try {
        File file = ResourceUtils.getFile(path);
        return new String(Files.readAllBytes(file.toPath()));
    } catch (IOException e) {
        e.printStackTrace();
    }

    return null;
}

Answer 5

All content in src/test/resources is copied into target/test-classes folder. So to get file from test resources during maven build you have to load it from test-classes folder, like that:

Paths.get(
    getClass().getProtectionDomain().getCodeSource().getLocation().toURI()
).resolve(
    Paths.get("somefile")
).toFile()

Break down:

1. getClass().getProtectionDomain().getCodeSource().getLocation().toURI() - give you URI to target/test-classes.
2. resolve(Paths.get("somefile")) - resolves someFile to target/test-classes folder.

Original anwser is taken from this

Answer 6

The simplest and clean solution I uses, suppose the name of the test class is TestQuery1 and there is a resources directory in your test folder as follows:

├── java
│   └── TestQuery1.java
└── resources
    └── TestQuery1
        ├── query.json
        └── query.rq

To get the URI of TestQuery1 do:

URL currentTestResourceFolder = getClass().getResource("/"+getClass().getSimpleName());

To get the URI of one of the file TestQuery1, do:

File exampleDir = new File(currentTestResourceFolder.toURI());
URI queryJSONFileURI = exampleDir.toURI().resolve("query.json");