Escape field name in jq that contains '@' and '-'? [duplicate]

Answer 1

The most robust alternative is to use the basic form:

.[KEY]

where KEY is a JSON string, including the outer quotation marks.

This form, however, must be pipelined, so you'd have to write:

jq '.abc|.["@def-ghi"]'

(The .[_] form can also be used for arrays, but of course _ would have to be an integer.)

Answer 2

You just need to quote the key:

$ echo '...' | jq '.abc."@def-ghi"'
"value1"