How do you write a full stack trace to the log?

Question

I was catching an exception and trying to write the stack trace to the logs like this:

log.warn(e.getMessage());

But all it said was

Answer 1

Using log4j this is done with:

logger.error("An error occurred", exception);

The first argument is a message to be displayed, the second is the exception (throwable) whose stacktrace is logged.

Another option is commons-logging, where it's the same:

log.error("Message", exception);

With java.util.logging this can be done via:

logger.log(Level.SEVERE, "Message", exception);

Answer 2

If you using Java 8 you can do the following:

LOGGER.error("Caught exception while methodX. Please investigate: " 
    + exception 
    + Arrays.asList(exception.getStackTrace())
    .stream()
    .map(Objects::toString)
    .collect(Collectors.joining("\n"))
);

Answer 3

You can use

logger.log(Level.WARN, "logged exception", ex);

or

logger.warn("logged exception", ex);

---

Resources :

• How to print the stack trace of an exception using Log4J (or Commons Logging)
• logging.apache.org - Category

Answer 4

Usually:

log.warn("message", e);

But it depends on your logging framework too.

Answer 5

In your exception method, the underlying String which contains the message is null.

The above answer, now struck out, still holds, except that e is not null, but the detailMessage private instance variable on the Throwable class is null, which is why e.getMessage() is the String null, but e.toString() (which calls underlying null detailMessage.toString) throws a NullPointerException.

Answer 6

If you are using a Java version previous to 8, you can try this:

            LOGGER.error("Error al recuperar proveedores de la base de datos: " + 
            e + Arrays.asList(e.getStackTrace()).stream().map(new Function(){
                    @Override
                    public Object apply(Object t) {
                        return t.toString();
                    }
                }).collect(Collectors.joining("\n")));