Sorting dropdown list using Javascript

Question

i want to sort the drop down items using javascript,can anyone tell me how to do this.

Answer 1

You could use jQuery and something like this:

$("#id").html($("#id option").sort(function (a, b) {
    return a.text == b.text ? 0 : a.text < b.text ? -1 : 1
}))

But it's probably better to ask why and what you're trying to accomplish.

Answer 2

DEPENDS ON JQUERY

function SortOptions(id) {
    var prePrepend = "#";
    if (id.match("^#") == "#") prePrepend = "";
    $(prePrepend + id).html($(prePrepend + id + " option").sort(
        function (a, b) { return a.text == b.text ? 0 : a.text < b.text ? -1 : 1 })
    );
}

Examples:

<select id="my-list-id"> is sorted with:

SortOptions("#my-list-id");

OR

SortOptions("my-list-id");

Answer 3

You can try JQuery sort function for this work --

Try this

HTML CODE -

<select id="ddlList">
  <option value="3">Three</option>
  <option value="1">One</option>
  <option value="1">one</option>
  <option value="1">a</option>
  <option value="1">b</option>
  <option value="1">A</option>
  <option value="1">B</option>
  <option value="0">Zero</option>
  <option value="2">Two</option>
  <option value="8">Eight</option>
</select>

JQUERY CODE -

$("#ddlList").html($('#ddlList option').sort(function(x, y) {        
     return $(x).text().toUpperCase() < $(y).text().toUpperCase() ? -1 : 1;
}));
$("#ddlList").get(0).selectedIndex = 0;
e.preventDefault();

OR

you can also use array sorting for this -

Try This

 var options = $('#ddlList option');
 var arr = options.map(function (_, o) { return { t: $(o).text(), v: o.value }; }).get();
 arr.sort(function (o1, o2) { return o1.t.toUpperCase() > o2.t.toUpperCase() ? 1 : o1.t.toUpperCase() < o2.t.toUpperCase() ? -1 : 0; });         
 options.each(function (i, o) {
     o.value = arr[i].v;
     $(o).text(arr[i].t);
 });

Answer 4

The answers provided didn't really suit my case so I made my own (especially not wanting jQuery). Figured it might help others.

sortDropDown(document.querySelector('select'));

function sortDropDown(d){
    //save option values
    var existingOptions=d.options; 

    //keep track of previously selected option
    var selectedOpt=d.selectedOptions[0].value;

    //turn nodeList into Array of values
    existingOptions=[].slice.call(existingOptions).map(function(a){return a.innerText});

    //make sure options are unique
    existingOptions = existingOptions.filter( function(value, index, self) { 
        return self.indexOf(value) === index;
    }); 

    //sort options
    existingOptions.sort();

    //keep "All" option as first element
    existingOptions.splice(0, 0, existingOptions.splice(existingOptions.indexOf('All'), 1)[0]);

    //repleace dropdown contents
    var t='';
    existingOptions.forEach(function(a){
        t+='<option '+(a==selectedOpt?'selected':'')+' value="'+a+'">'+a+'</option>';
    });
    d.innerHTML=t;
}

Answer 5

<select id="foo" size="10">
  <option value="3">three</option>
  <option value="1">one</option>
  <option value="0">zero</option>
  <option value="2">two</option>
</select>
<script>
  // WARN: won't handle OPTGROUPs!
  var sel = document.getElementById('foo');
  // convert OPTIONs NodeList to an Array
  // - keep in mind that we're using the original OPTION objects
  var ary = (function(nl) {
    var a = [];
    for (var i = 0, len = nl.length; i < len; i++)
      a.push(nl.item(i));
    return a;
  })(sel.options);
  // sort OPTIONs Array
  ary.sort(function(a,b){
    // sort by "value"? (numeric comparison)
    // NOTE: please remember what ".value" means for OPTION objects
    return a.value - b.value;
    // or by "label"? (lexicographic comparison) - case sensitive
    //return a.text < b.text ? -1 : a.text > b.text ? 1 : 0;
    // or by "label"? (lexicographic comparison) - case insensitive
    //var aText = a.text.toLowerCase();
    //var bText = b.text.toLowerCase();
    //return aText < bText ? -1 : aText > bText ? 1 : 0;
  });
  // remove all OPTIONs from SELECT (don't worry, the original
  // OPTION objects are still referenced in "ary") ;-)
  for (var i = 0, len = ary.length; i < len; i++)
    sel.remove(ary[i].index);
  // (re)add re-ordered OPTIONs to SELECT
  for (var i = 0, len = ary.length; i < len; i++)
    sel.add(ary[i], null);
</script>

Answer 6

FOR DROPDOWN FOR WHOLE PROJECT

$(document).ready(function () {
    $.when($('select').addClass('auto-drop-sort')).then($.fn.sortDropOptions("auto-drop-sort"))
})

/*sort all dropdown*/
$.fn.sortDropOptions = function(dropdown_class){
    var prePrepend = ".";
    if (dropdown_class.match("^.") == ".") prePrepend = "";
    var myParent = $(prePrepend + dropdown_class);
    $.each(myParent, function(index, val) {
        /*if any select tag has this class 'manual-drop-sort' this function wont work for that particular*/
        if ( ! $(val).hasClass('manual-drop-sort') ) {
            var selectedVal = $(val).val()
            $(val).html($(val).find('option').sort(
                function (a, b) {
                    if ( a.value != -1 && a.value != 0 && a.value != '' ) {
                        return a.text == b.text ? 0 : a.text < b.text ? -1 : 1 
                    }
                })
            );
            $(val).val(selectedVal)
        }else{
            /* set custom sort for individual select tag using name/id */
        }
    });
}