Let\'s say I have two dataframes, and the column names for both are:
table 1 columns:
[ShipNumber, TrackNumber, ShipDate, Quantity, Weight]
table 2 columns:
[Shi
Use merge() and concat(). Then drop any duplicate cases where both A and B match (thanks @Scott Boston for that final step).
df1 = pd.DataFrame({'A':[3,2,1,4], 'B':[7,8,9,5]})
df2 = pd.DataFrame({'A':[1,5,6,4], 'B':[4,1,8,5]})
df1 df2
A B A B
0 1 7 0 1 4
1 2 8 1 5 1
2 3 9 2 6 8
3 4 5 3 4 5
With these data frames we should see:
df1.loc[0] matches A on df2.loc[0] df1.loc[1] matches B on df2.loc[2]df1.loc[3] matches both A and B on df2.loc[3]We'll use suffixes to keep track of what matched where:
suff_A = ['_on_A_match_1', '_on_A_match_2']
suff_B = ['_on_B_match_1', '_on_B_match_2']
pd.concat([df1.merge(df2, on='A', suffixes=suff_A),
df1.merge(df2, on='B', suffixes=suff_B)])
A A_on_B_match_1 A_on_B_match_2 B B_on_A_match_1 B_on_A_match_2
0 1.0 NaN NaN NaN 9.0 4.0
1 4.0 NaN NaN NaN 5.0 5.0
0 NaN 2.0 6.0 8.0 NaN NaN
1 NaN 4.0 4.0 5.0 NaN NaN
Note that the second and fourth rows are duplicate matches (for both data frames, A = 4 and B = 5). We need to remove one of those sets.
dupes = (df.B_on_A_match_1 == df.B_on_A_match_2) # also could remove A_on_B_match
df.loc[~dupes]
A A_on_B_match_1 A_on_B_match_2 B B_on_A_match_1 B_on_A_match_2
0 1.0 NaN NaN NaN 9.0 4.0
0 NaN 2.0 6.0 8.0 NaN NaN
1 NaN 4.0 4.0 5.0 NaN NaN
I would suggest this alternate way for doing merge like this. This seems easier for me.
table1["id_to_be_merged"] = table1.apply(
lambda row: row["ShipNumber"] if pd.notnull(row["ShipNumber"]) else row["TrackNumber"], axis=1)
You can add the same column in table2 as well if needed and then use in left_in or right_on based on your requirement.