Join one to many and retrieve single result

Question

I have two tables, in PostgreSQL if that matters, with one to many relations. I need to join them so that for each \"one\" I only get single result from the \"many\" table. Not

Answer 1

Simpler, shorter, faster with PostgreSQL's DISTINCT ON:

SELECT DISTINCT ON (a.id)
       a.id, a.name, a.date, b.code1, b.code2
FROM   table_a a
LEFT   JOIN table_b b USING (id)
ORDER  BY a.id, b.sort

Details, explanation, benchmark and links in this closely related answer.
I use a LEFT JOIN, so that rows from table_a without any matching row in table_b are not dropped.

Side notes:

While being allowed in PostgreSQL, it's unwise to use date as column name. It's a reserved word in every SQL standard and a type name in PsotgreSQL.

It's also an anti-pattern to name an ID column id. Not descriptive and not helpful. One (of many) possible naming convention would be to name it after the table where it is primary key: table_a_id. Same name for foreign keys referencing it (if no other natural name takes precedence).

Answer 2

PostgreSQL supports window function. Try this,

SELECT d.ID, d.NAME, d.DATE, d.CODE1, d.CODE2
FROM
(
  SELECT  a.ID, a.NAME, a.DATE,
          b.CODE1, b.CODE2,
          ROW_NUMBER() OVER(PARTITION BY a.ID ORDER BY b.SORT ASC, b.CODE2 DESC) AS ROWNUM
  FROM    TableA a
          INNER JOIN TableB b
            ON a.ID = b.ID
) d
WHERE d.RowNum = 1

SQLFiddle Demo

Answer 3

Here's what I'd do on SQL Server.

SELECT a.ID,
    a.NAME,
    a.DATE,
    b.CODE1,
    b.CODE2
FROM TABLE_A a
JOIN TABLE_B b
    on a.ID = b.ID
WHERE b.SORT = (SELECT MIN(SORT) 
    FROM TABLE_B
    WHERE ID = b.ID)