Regular expression with an = and a ;

Question

I\'m trying to use a regular expression to find all substrings that start with an equals sign (=) and ends with a semicolon (;) with any number of char

Answer 1

This looks for "any number of = signs, including 0"

=*;

If you want "= followed by any number of other characters" you want

=.*;

However, that will match greedily - if you want lazy matching (so that it stops one group when it finds the next semicolon) you might want:

=.*?;

Answer 2

Something like =.*;

Answer 3

This may be what you are looking for. You need to specify a character set or wild card character that you are applying the asterisk to.

"=([^;]*);"

You can also use the reluctant quantifier:

"=(.*?);"

Using the parenthesis you now have groups. I believe the first group is the whole entire match, and group[1] is the group found within the parenthesis.

The code may look something like:

Regex r = new Regex("=([^;]*);");
Match m = r.Match(yourData);
while (m.Success) {
    string match = m.Groups[1];
    // match should be the text between the '=' and the ';'.
}

Answer 4

The regex you provided would match ;, ===;, ..., ================;. How about =.*; (or =.*?; if non-greedy is needed)?

Answer 5

An excellent source for learning about regexp in Java: sun's book about regexp