How to compare two dates to find time difference in SQL Server 2005, date manipulation

Question

I have two columns:

job_start                         job_end
2011-11-02 12:20:37.247           2011-11-02 13:35:14.613

How would it be po

Answer 1

Declare the Start and End date DECLARE @SDATE AS DATETIME

TART_DATE  AS DATETIME
DECLARE @END_-- Set Start and End date
SET @START_DATE = GETDATE()
SET @END_DATE    = DATEADD(SECOND, 3910, GETDATE())

-- Get the Result in HH:MI:SS:MMM(24H) format SELECT CONVERT(VARCHAR(12), DATEADD(MS, DATEDIFF(MS, @START_DATE, @END_DATE), 0), 114) AS TimeDiff

Answer 2

Take a look at the DateDiff() function.

-- Syntax
-- DATEDIFF ( datepart , startdate , enddate )

-- Example usage
SELECT DATEDIFF(DAY, GETDATE(), GETDATE() + 1) AS DayDiff
SELECT DATEDIFF(MINUTE, GETDATE(), GETDATE() + 1) AS MinuteDiff
SELECT DATEDIFF(SECOND, GETDATE(), GETDATE() + 1) AS SecondDiff
SELECT DATEDIFF(WEEK, GETDATE(), GETDATE() + 1) AS WeekDiff
SELECT DATEDIFF(HOUR, GETDATE(), GETDATE() + 1) AS HourDiff
...

You can see it in action / play with it here

Answer 3

If your database StartTime = 07:00:00 and endtime = 14:00:00, and both are time type. Your query to get the time difference would be:

SELECT TIMEDIFF(Time(endtime ), Time(StartTime )) from tbl_name

If your database startDate = 2014-07-20 07:00:00 and endtime = 2014-07-20 23:00:00, you can also use this query.

Answer 4

Take a look at DATEDIFF, this should be what you're looking for. It takes the two dates you're comparing, and the date unit you want the difference in (days, months, seconds...)

Answer 5

I used following logic and it worked for me like marvel:

CONVERT(TIME, DATEADD(MINUTE, DATEDIFF(MINUTE, AP.Time_IN, AP.Time_OUT), 0))