How to generate random number with the specific length in python

Question

Let say I need a 3 digit number, so it would be something like:

>>> random(3)
563

or

>>> random(5)
26748
>> random(2)
56


        

Answer 1

You could create a function who consumes an list of int, transforms in string to concatenate and cast do int again, something like this:

import random

def generate_random_number(length):
    return int(''.join([str(random.randint(0,10)) for _ in range(length)]))

Answer 2

To get a random 3-digit number:

from random import randint
randint(100, 999)  # randint is inclusive at both ends

(assuming you really meant three digits, rather than "up to three digits".)

To use an arbitrary number of digits:

from random import randint

def random_with_N_digits(n):
    range_start = 10**(n-1)
    range_end = (10**n)-1
    return randint(range_start, range_end)

print random_with_N_digits(2)
print random_with_N_digits(3)
print random_with_N_digits(4)

Output:

33
124
5127