Posting array from form

Question

I have a form on my page with a bunch of inputs and some hidden fields, I\'ve been asked to pass this data through a \"post array\" only im unsure on how to do this,

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Answer 1

Give each input a name in array format:

<input type="hidden" name="data[EstPriceInput]" value="" />

Then the in PHP $_POST['data']; will be an array:

  print_r($_POST);         // print out the whole post
  print_r($_POST['data']); // print out only the data array

Answer 2

If you want everything in your post to be as $Variables you can use something like this:

foreach($_POST as $key => $value) { eval("$" . $key . " = " . $value"); }

Answer 3

When you post that data, it is stored as an array in $_POST.

You could optionally do something like:

<input name="arrayname[item1]">
<input name="arrayname[item2]">
<input name="arrayname[item3]">

Then:

$item1 = $_POST['arrayname']['item1'];
$item2 = $_POST['arrayname']['item2'];
$item3 = $_POST['arrayname']['item3'];

But I fail to see the point.

Answer 4

You're already doing that, as a matter of fact. When the form is submitted, the data is passed through a post array ($_POST). Your process.php is receiving that array and redistributing its values as individual variables.

Answer 5

What you are doing is not necessarily bad practice but it does however require an extraordinary amount of typing. I would accomplish what you are trying to do like this.

foreach($_POST as $var => $val){
    $$var = $val;
}

This will take all the POST variables and put them in their own individual variables. So if you have a input field named email and the luser puts in Someone@example.com you will have a var named $email with a value of "Someone@example.com".

Answer 6

You can use the built-in function:

extract($_POST);

it will create a variable for each entry in $_POST.