Checking if a value is equal to any value in an array [duplicate]

Answer 1

The hint is in your question. Use any. This uses a generator expression to check if it is True or False.

any(first == c for c in letter)

Answer 2

Try using the in keyword:

if first in letter:

On your current code, you are comparing a string character (first which equals the first character in word) to a list. So, let's say my input is "a word". What your code is actually doing is:

if "a" == ["a", "b", "c"]:

which will always be false.

Using the in keyword however is doing:

if "a" in ["a", "b", "c"]:

which tests whether "a" is a member of ["a", "b", "c"] and returns true in this case.

Answer 3

You need to use the in operator. Use if first in letter:.

>>> letter = ["a", "b", "c"]
>>> word = raw_input('Enter a word:')
Enter a word:ant
>>> first = word[0]
>>> first in letter
True

And one False test,

>>> word = raw_input('Enter a word:')
Enter a word:python
>>> first = word[0]
>>> first in letter
False

Answer 4

The problem as I see it, is that you are asking does a character equal an array. This will always return false.

Try using a loop to check 'first' against each item in 'letter'. Let me know if you need help on figuring out how to do this.