How can I pass main's *argv[] to a function?

Question

I have a program that can accept command-line arguments and I want to access the arguments, entered by the user, from a function. How can I pass the *argv[], from <

Answer 1

Just write a function such as

void parse_cmdline(int argc, char *argv[])
{
    // whatever you want
}

and call that in main as parse_cmdline(argc, argv). No magic involved.

In fact, you don't really need to pass argc, since the final member of argv is guaranteed to be a null pointer. But since you have argc, you might as well pass it.

If the function need not know about the program name, you can also decide to call it as

parse_cmdline(argc - 1, argv + 1);

Answer 2

SomeResultType ParseArgs( size_t count, char**  args ) {
    // parse 'em
}

Or...

SomeResultType ParseArgs( size_t count, char*  args[] ) {
    // parse 'em
}

And then...

int main( int size_t argc, char* argv[] ) {
    ParseArgs( argv );
}

Answer 3

Just pass argc and argv to your function.