What is the correct way to query MongoDB for _id using string by using Python?

Question

I am using pymongo driver. Supposedly, one can use a string to query the _id field of a document, like this:

thing = db.things.find_one({\'_id\':\'4ea113d6b6848         


        

Answer 1

It should be :

from pymongo.objectid import ObjectId   
thing = db.things.find_one({'_id': ObjectId('4ea113d6b684853c8e000001') })

EDIT: The current import is: from bson.objectid import ObjectId

Answer 2

thing = db.things.find_one({'_id':ObjectId('4ea113d6b684853c8e000001')}) should work

Answer 3

To print it:

import pymongo
from bson.objectid import ObjectId    
print(db.things.find_one({'_id': ObjectId('4ea113d6b684853c8e000001')}))

if you don't want to print, store in other variable

Answer 4

PyMongo documentation does not seem to be in sync with the current version. ObjectIds are now under bson.objectid namespace. If I remember right, they have been that way since version 2.3. Use from bson.objectid import ObjectId.

Answer 5

PyMongo has changed its structure. ObjectID is no longer imported from pymongo, but from bson. It should now be:

from bson.objectid import ObjectId
thing = db.things.find_one({'_id': ObjectId('4ea113d6b684853c8e000001')})

As a reminder, per pypi/pymongo, do not install the “bson” package. PyMongo comes with its own bson package; doing “pip install bson” installs a third-party package that is incompatible with PyMongo.