I\'m writing a Makefile, and some of the commands the makefile runs require a password. I\'d like to give the user the ability to either pass this in as a Makefile variable usi
A couple of things:
$ for dereferencing shell variable pwd is being interpreted by make. You can escape it from make with $$make is invoking the shell as Posix compatible /bin/sh instead of /bin/bash. As such, the -s option to read is not supported.Try this instead:
PASSWORD ?= $(shell bash -c 'read -s -p "Password: " pwd; echo $$pwd')
This worked for me on Ubuntu 12.04 / GNU make 3.81 / bash 4.2.25(1)
And on OSX 10.8.5 / make 3.81 / bash 3.2.48(1):
$ cat Makefile
PASSWORD ?= $(shell bash -c 'read -s -p "Password: " pwd; echo $$pwd')
all:
echo The password is $(PASSWORD)
$ make
Password: echo The password is 1234
The password is 1234
$
Update - @user5321531 pointed out that we can use POSIX sh instead of bash, and temporarily suppress echo with stty:
PASSWORD ?= $(shell stty -echo; read -p "Password: " pwd; stty echo; echo $$pwd)
To answer @joeb 's question:
$ make; echo "---Makefile---"; cat Makefile
Password: <hidden>
test
test
---Makefile---
all: first second
PASSWORD ?= $(shell read -s -p "Password: " pass; echo $$pass)
define formatted
first:
@echo $1
second:
@echo $1
endef
$(eval $(call formatted,$(PASSWORD)))