How to check if a key exists in Json Object and get its value [duplicate]

Answer 1

Use below code to find key is exist or not in JsonObject. has("key") method is used to find keys in JsonObject.

containerObject = new JSONObject(container);
//has method
if (containerObject.has("video")) {
    //get Value of video
    String video = containerObject.optString("video");
}

If you are using optString("key") method to get String value then don't worry about keys are existing or not in the JsonObject.

Answer 2

containerObject = new JSONObject(container);
if (containerObject.has("video")) { 
   //get Value of video
}

Answer 3

JSONObject root= new JSONObject();
JSONObject container= root.getJSONObject("LabelData");

try{
//if key will not be available put it in the try catch block your program 
 will work without error 
String Video=container.getString("video");
}
catch(JsonException e){

 if key will not be there then this block will execute

 } 
 if(video!=null || !video.isEmpty){
  //get Value of video
}else{
  //other vise leave it
 }

i think this might help you

Answer 4

Please try this one..

JSONObject jsonObject= null;
try {
     jsonObject = new JSONObject("result........");
     String labelDataString=jsonObject.getString("LabelData");
     JSONObject labelDataJson= null;
     labelDataJson= new JSONObject(labelDataString);
     if(labelDataJson.has("video")&&labelDataJson.getString("video")!=null){
       String video=labelDataJson.getString("video");
     }
    } catch (JSONException e) {
      e.printStackTrace();
 }

Answer 5

From the structure of your source Object, I would try:

containerObject= new JSONObject(container);
 if(containerObject.has("LabelData")){
  JSONObject innerObject = containerObject.getJSONObject("LabelData");
     if(innerObject.has("video")){
        //Do with video
    }
}

Answer 6

Use:

if (containerObject.has("video")) {
    //get value of video
}