firebase retrieve data by using orderByKey() and equalTo()

Question

So I\'m trying to find the data \"aaaaabbbbbbaaaa\" in this structure:

disney
 studentList
 -Jh46tlaNFx_YmgA8iMJ: \"aaaaabbbbbbaaaa\"
 -Jh474kAvoekE4hC7W3b:\"54c         


        

Answer 1

In the data sample that you've given, there is no node under studenList with a key of 54ca2c11d1afc1612871624a.

Your keys are -Jh46tlaNFx_YmgA8iMJ and -Jh474kAvoekE4hC7W3b. You can easily determine this yourself by:

ref.child("studentList").orderByKey().on("child_added", function(snapshot) {
  console.log(snapshot.key()); // on newer SDKs, this may be snapshot.key
});

You seem to want to order the nodes by their value, but that is not an operation that is available on Firebase at the moment. Firebase can only query children by a value of a named property, the key or its priority. So if you'd change the data structure to:

disney
 studentList
   -Jh46tlaNFx_YmgA8iMJ:
     name: "aaaaabbbbbbaaaa"
   -Jh474kAvoekE4hC7W3b:
     name: "54ce1cbec4335cd3186105dc"

You could get the children order by name with:

ref.child("studentList")
   .orderByChild("name")
   .equalTo("54ca2c11d1afc1612871624a")
   .on("child_added", function(snapshot) {
      console.log(snapshot.val());
    });

Just a side node: if your actual node values are like the ones in the sample you provided, you might want to consider using the values as the keys; they already seem pretty unique to my untrained eye.