RegEx to extract URL from CSS background styling

Question

I have a string in this form:

url(\"http://www.example.com/imgs/backgrounds/bg80.jpg\") repeat scroll 10% 0% transparent

This is from a CSS sty

Answer 1

A background url can have ' or " or none around the url inside the parenthesis

Valid urls

• url("http://www.example.com/imgs/backgrounds/bg80.jpg")
• url('http://www.example.com/imgs/backgrounds/bg80.jpg')
• url(http://www.example.com/imgs/backgrounds/bg80.jpg)

So for a generic solution you could use

var background = 'url("http://www.example.com/imgs/backgrounds/bg80.jpg") repeat scroll 10% 0% transparent',
    reg = /(?:\(['"]?)(.*?)(?:['"]?\))/,
    extracterUrl = reg.exec(background)[1];