Is it possible to draw a filled circle with cocos2d ? An outlined circle can be done using the drawCircle() function, but is there a way to fill it in a certain color? Perhaps b
I also wonder this, but haven't really accomplished doing it. I tried using CGContext stuff that Grouchal tipped above, but I can't get it to draw anything on the screen. This is what I've tried:
-(void) draw
{
[self makestuff:UIGraphicsGetCurrentContext()];
}
-(void)makestuff:(CGContextRef)context
{
// Drawing lines with a white stroke color
CGContextSetRGBStrokeColor(context, 1.0, 1.0, 1.0, 1.0);
// Draw them with a 2.0 stroke width so they are a bit more visible.
CGContextSetLineWidth(context, 2.0);
// Draw a single line from left to right
CGContextMoveToPoint(context, 10.0, 30.0);
CGContextAddLineToPoint(context, 310.0, 30.0);
CGContextStrokePath(context);
// Draw a connected sequence of line segments
CGPoint addLines[] =
{
CGPointMake(10.0, 90.0),
CGPointMake(70.0, 60.0),
CGPointMake(130.0, 90.0),
CGPointMake(190.0, 60.0),
CGPointMake(250.0, 90.0),
CGPointMake(310.0, 60.0),
};
// Bulk call to add lines to the current path.
// Equivalent to MoveToPoint(points[0]); for(i=1; i
These methods are defined in a cocos node class, and the makestuff method I borrowed from a code example...
NOTE: I'm trying to draw any shape or path and fill it. I know that the code above only draws lines, but I didn't wanna continue until I got it working.
EDIT: This is probably a crappy solution, but I think this would at least work.
Each CocosNode has a texture (Texture2D *). Texture2D class can be initialized from an UIImage. UIImage can be initialized from a CGImageRef. It is possible to create a CGImageRef context for the quartz lib.
So, what you would do is:
Question is if this would be fast enough to do. I would prefer if you could sort of get a CGImageRef from the CocosNode directly and draw into it instead of going through all these steps, but I haven't found a way to do that yet (and I'm kind of a noob at this so it's hard to actually get somewhere at all).