Is there a way to get the latest tag of a given repo using github API v3

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南笙
南笙 2021-02-02 11:10

I am relatively new to the github api and I am struggling to get the latest tag of a given repo.

Q: Why I need that ?

A:

4条回答
  •  感情败类
    2021-02-02 11:52

    Using GraphQL API v4, you can get the last tag by alphabetical or commit date. For instance by commit date (eg the tag that point to the most recent commit) :

    {
      repository(owner: "bertrandmartel", name: "caipy-dashboard") {
        refs(refPrefix: "refs/tags/", first: 1, orderBy: {field: TAG_COMMIT_DATE, direction: DESC}) {
          edges {
            node {
              name
              target {
                oid
                ... on Tag {
                  message
                  commitUrl
                  tagger {
                    name
                    email
                    date
                  }
                }
              }
            }
          }
        }
      }
    }
    

    test it in the explorer

    Note that if the tag is a lightweight tag, there will be no taggeror message field. You can also use field: ALPHABETICAL for the last tag in alphabetical order.

    If you want to get the last tag that was created (which could be different from the tag that point to the most recent commit, or the last tag in alphabetical order), it's only possible for annotated tag since their creation date is stored and will be available in the tagger field.

    To get the last created tag, you would get all the tags and filter the most recent date in data.repository.refs.edges.node.target.tagger.date field in the response of the following request :

    {
      repository(owner: "google", name: "gson") {
        refs(refPrefix: "refs/tags/", first: 100, orderBy: {field: TAG_COMMIT_DATE, direction: DESC}) {
          edges {
            node {
              name
              target {
                oid
                ... on Tag {
                  commitUrl
                  tagger {
                    date
                  }
                }
              }
            }
          }
        }
      }
    }
    

    test it in the explorer

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