How can I log current line, and stack info with Python?

Question

I have logging function as follows.

logging.basicConfig(
    filename = fileName,
    format = \"%(levelname) -10s %(asctime)s %(message)s\",
    level = logging         


        

Answer 1

This is based on @mouad's answer but made more useful (IMO) by including at each level the filename (but not its full path) and line number of the call stack, and by leaving the stack in most-recently-called-from (i.e. NOT reversed) order because that's the way I want to read it :-)

Each entry has file:line:func() which is the same sequence as the normal stacktrace, but all on the same line so much more compact.

import inspect

def callers(self):
    caller_list = []
    frame = inspect.currentframe()
    while frame.f_back:
        caller_list.append('{2}:{1}:{0}()'.format(frame.f_code.co_name,frame.f_lineno,frame.f_code.co_filename.split("\\")[-1]))
        frame = frame.f_back
    callers =  ' <= '.join(caller_list)
    return callers

You may need to add an extra f_back if you have any intervening calls to produce the log text.

        frame = inspect.currentframe().f_back

Produces output like this:

file2.py:620:func1() <= file3.py:211:func2() <= file3.py:201:func3() <= main.py:795:func4() <= file4.py:295:run() <= main.py:881:main()

I only need this stacktrace in two key functions, so I add the output of callers into the text in the logger.debug() call, like htis:

logger.debug("\nWIRE: justdoit request -----\n"+callers()+"\n\n")