Groovy list.sort by first, second then third elements

Question

I have a groovy list of lists i.e.

list = [[2, 0, 1], [1, 5, 2], [1, 0, 3]]

I would like sort it by order of the first element, then second, th

Answer 1

Here is another method using Groovy's Spaceship and Elvis operators:

​def list = [[2, 0, 1], [1, 5, 2], [1, 0, 3]]

list.sort { a, b ->
   a[0] <=> b[0] ?: a[1] <=> b[1] ?: a[2] <=> b[2]
}

assert list == [[1, 0, 3], [1, 5, 2], [2, 0, 1]]​

Source: Groovier way of sorting over multiple fields in a list of maps in groovy