Groovy list.sort by first, second then third elements

Question

I have a groovy list of lists i.e.

list = [[2, 0, 1], [1, 5, 2], [1, 0, 3]]

I would like sort it by order of the first element, then second, th

Answer 1

If you want to sort arrays of arbitrary (though homogenous) length, you can use this and it will do it in a single pass:

def list = [[2, 0, 1], [1, 5, 2], [1, 0, 3]]

list.sort { a, b -> 
    for (int i : (0.. b[i])
        if (comparison) return comparison
    } 
    return 0
}

assert list == [[1, 0, 3], [1, 5, 2], [2, 0, 1]]