How to safely get the file extension from a URL?

Question

Consider the following URLs

http://m3u.com/tunein.m3u
http://asxsomeurl.com/listen.asx:8024
http://www.plssomeotherurl.com/station.pls?id=111
http://22.198.133.16:802         


        

Answer 1

To get the content-type you can write a function one like I have written using urllib2. If you need to utilize page content anyway it is likely that you will use urllib2 so no need to import os.

import urllib2

def getContentType(pageUrl):
    page = urllib2.urlopen(pageUrl)
    pageHeaders = page.headers
    contentType = pageHeaders.getheader('content-type')
    return contentType